document.write( "Question 238852: Last weekend two college students were returning to school 200 miles away. During a blizzard, they were only able to average 25 miles per hour. For the rest of their trip, they averaged 55 miles per hour. If the entire trip took 4 hours, how long were they driving in the blizzard? \n" ); document.write( "
Algebra.Com's Answer #175485 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "200=25T+55(4-T)
\n" ); document.write( "200=25T+220-55T
\n" ); document.write( "200-220=-30T
\n" ); document.write( "T=-20/-30
\n" ); document.write( "T=2/3 OR 40 MINUTES DRIVING IN THE BLIZZARD.
\n" ); document.write( "4-2/3=3 1/3 OR 10/3 HOURS DRIVING @ 55 MPH.
\n" ); document.write( "PROOF:
\n" ); document.write( "200=25*2/3+55*10/3
\n" ); document.write( "200=50/3+550/3
\n" ); document.write( "200=600/3
\n" ); document.write( "200=200
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