document.write( "Question 238816: What is X if, logx^(16)=-2
\n" ); document.write( "I bet it's not -8 that would be too easy. My mind is spinning, help please!!!
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Algebra.Com's Answer #175477 by Alan3354(69443)\"\" \"About 
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What is X if, logx^(16)=-2
\n" ); document.write( "Is it log(x^16) ? If so,
\n" ); document.write( "log(x^16) = -2
\n" ); document.write( "16log(x) = -2
\n" ); document.write( "log(x) = -1/8
\n" ); document.write( "x = 10^(-1/8)
\n" ); document.write( "x = ~0.74989
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