document.write( "Question 238741: Use de Moivre's Theorem to find the square root of -5+12i. \r
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document.write( "r=13 √ 25+144 = √ 169
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document.write( "arctan= (12 ÷ 5) = 1.1760...\r
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document.write( "13(cos 1.7600... +2πn + isin 1.1760...)\r
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document.write( "13^(1/2)(((cos 1.1760... + 2πn)/2)+((isin1.76)/2)\r
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document.write( "This is what I have done so far, please tell me if it is correct, and I am unsure as to what steps to make next. \n" );
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Algebra.Com's Answer #175462 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Use de Moivre's Theorem to find the square root of -5+12i. \n" ); document.write( "r=13 √ 25+144 = √ 169 \n" ); document.write( "------------------------ \n" ); document.write( "angle A = arccos(-5/13) \n" ); document.write( "z = 13(cos(A) + isin(A)) A =~ 112.62º \n" ); document.write( "sqrt(z) = sqrt(13)*(cos(A/2) + isin(A/2)) \n" ); document.write( "sqrt(z) = sqrt(13)*(0.5547 + i*0.8321) \n" ); document.write( "= 2 + 3i \n" ); document.write( "---------- \n" ); document.write( "arctan= (12 ÷ 5) = 1.1760... \n" ); document.write( "13(cos 1.7600... +2πn + isin 1.1760...) \n" ); document.write( "13^(1/2)(((cos 1.1760... + 2πn)/2)+((isin1.76)/2) \n" ); document.write( " \n" ); document.write( " |