document.write( "Question 238570: Solve by the elimination method.
\n" ); document.write( ".05x+.25y=44
\n" ); document.write( ".15x+.05y=48
\n" ); document.write( "

Algebra.Com's Answer #175430 by checkley77(12844)\"\" \"About 
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.05x+.25y=44 multiply by -3 & add
\n" ); document.write( ".15x+.05y=48
\n" ); document.write( "-.15x-.75y=-132
\n" ); document.write( "--------------------
\n" ); document.write( "-.70y=-84
\n" ); document.write( "y=-84/-.70
\n" ); document.write( "y=120 ans.
\n" ); document.write( ",05x+.25*120=44
\n" ); document.write( ".05x+30=44
\n" ); document.write( ".05x=44-30
\n" ); document.write( ".05x=14
\n" ); document.write( "x=14/.05
\n" ); document.write( "x=280 ans.
\n" ); document.write( "Proof:
\n" ); document.write( ".15*280+.05*120=48
\n" ); document.write( "42+6=48
\n" ); document.write( "48=48
\n" ); document.write( "
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