document.write( "Question 238570: Solve by the elimination method.
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document.write( ".05x+.25y=44
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document.write( ".15x+.05y=48 \n" );
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Algebra.Com's Answer #175430 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .05x+.25y=44 multiply by -3 & add \n" ); document.write( ".15x+.05y=48 \n" ); document.write( "-.15x-.75y=-132 \n" ); document.write( "-------------------- \n" ); document.write( "-.70y=-84 \n" ); document.write( "y=-84/-.70 \n" ); document.write( "y=120 ans. \n" ); document.write( ",05x+.25*120=44 \n" ); document.write( ".05x+30=44 \n" ); document.write( ".05x=44-30 \n" ); document.write( ".05x=14 \n" ); document.write( "x=14/.05 \n" ); document.write( "x=280 ans. \n" ); document.write( "Proof: \n" ); document.write( ".15*280+.05*120=48 \n" ); document.write( "42+6=48 \n" ); document.write( "48=48 \n" ); document.write( " \n" ); document.write( " |