document.write( "Question 238653: solve using addition method
\n" ); document.write( "3/7x+5/9y=27
\n" ); document.write( "1/9x+2/7y=7 \n" ); document.write( "
Algebra.Com's Answer #175426 by checkley77(12844)\"\" \"About 
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3X/7+5Y/9=27 MULTIPLY BY 1/9
\n" ); document.write( "1X/9+2Y/7=7 MULTIPLY BY -3/7 & ADD
\n" ); document.write( "(3X/7)(1/9)+(5Y/9)(1/9)=27(1/9)
\n" ); document.write( "(X/9)(-3/7)+(2Y/7)(-3/7)=7(-3/7)
\n" ); document.write( "----------------------------------------
\n" ); document.write( "3X/27-3X/27+5Y/81-6Y/49=27/9-21/7
\n" ); document.write( "5Y/81-6Y/49=3-3
\n" ); document.write( "(5Y*49-6Y*81)/81*49=0
\n" ); document.write( "245y-486y=0
\n" ); document.write( "-241y=0
\n" ); document.write( "y=0 ans.
\n" ); document.write( "3x/7=27
\n" ); document.write( "3x=27*7
\n" ); document.write( "3x=189
\n" ); document.write( "x=189/3
\n" ); document.write( "x=63 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "63/9+2*0/7=7
\n" ); document.write( "7=7 \n" ); document.write( "
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