document.write( "Question 238723: 2x+3=5y
\n" ); document.write( "2x+y=7 \n" ); document.write( "
Algebra.Com's Answer #175415 by checkley77(12844)\"\" \"About 
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2x-5y=-3
\n" ); document.write( "-(2x+y=7) subtract
\n" ); document.write( "---------------
\n" ); document.write( "-6y=-10
\n" ); document.write( "y=-10/-6
\n" ); document.write( "y=5/3 ans
\n" ); document.write( "2x-5*5/3=-3
\n" ); document.write( "2x-25/3=-3
\n" ); document.write( "2x=25/3-3
\n" ); document.write( "2x=25/3-9/3
\n" ); document.write( "2x=16/3
\n" ); document.write( "x=(16/3)/2
\n" ); document.write( "x=(16/3*1/2
\n" ); document.write( "x=16/6
\n" ); document.write( "x=8/3 anw.
\n" ); document.write( "Proof:
\n" ); document.write( "2*8/3+5/3=7
\n" ); document.write( "16/3+5/3=7
\n" ); document.write( "21/3=7
\n" ); document.write( "7=7
\n" ); document.write( " \n" ); document.write( "
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