document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=238580>Question 238580</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -2x-10y=-12<BR>\n" );
document.write( "3x+y=4<BR>\n" );
document.write( "find value of (x,y) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #175399 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=175399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let's multiply the second equation by 10 so it will look like this:<BR>\n" );
document.write( " -2x   -10y= -12<BR>\n" );
document.write( "(10)3x+(10)y=(10)4  Now we can add both equation (note: the y cancels out)<BR>\n" );
document.write( "which leaves us with:<BR>\n" );
document.write( "28x = 28<BR>\n" );
document.write( "x = 1 Now plug 1 into either equation and you get <BR>\n" );
document.write( "y = 1<BR>\n" );
document.write( "Plug these into the equations and it works out. <BR>\n" );
document.write( "RJ Toftness<BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
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