document.write( "Question 238680: coordinate geometry: find two points on the perpendicular bisector of AB.
\n" ); document.write( "verify your answer results by showing each point is equidistant from A and B
\n" ); document.write( "A(0,0),B(0,4) \n" ); document.write( "
Algebra.Com's Answer #175373 by Alan3354(69443)\"\" \"About 
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Since both points are on the y-axis, the perpendicular bisector will be parallel to the x-axis and 2 units from it.
\n" ); document.write( "Any point on y = 2 fits.
\n" ); document.write( "(1,2)
\n" ); document.write( "(5,2)
\n" ); document.write( "(-55,2)
\n" ); document.write( "(x,2) works.
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\n" ); document.write( "To find the distance for 2 of the points:
\n" ); document.write( "(1,2) from (0,0)
\n" ); document.write( "s^2 = diffy^2 + diffx^2 = 1 + 4
\n" ); document.write( "s^2 = 5
\n" ); document.write( "(1,2) from (0,4)
\n" ); document.write( "s^2 = 1 + 4
\n" ); document.write( "Same distance (if the squares are equal, they're equal)
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\n" ); document.write( "(-55,2) from (0,0)
\n" ); document.write( "s^2 = 55^2 + 4 = 3029
\n" ); document.write( "(-55,2) from (0,4)
\n" ); document.write( "s^2 = 3025 + 4 = 3029 --> same distance sqrt(3029)
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