document.write( "Question 238614: Solve each system of equations by graphing. I dont understand how to switch it into a slope intercept form. I've seen many examples from the book but dont understand how they get the numbers. Will you explain it to me please?\r
\n" ); document.write( "\n" ); document.write( "x + 2y = 6
\n" ); document.write( "2x + y = 9
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Algebra.Com's Answer #175307 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll get the equations into slope intercept form and let you do the graphing.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B2y=6\" Start with the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"2y=6-x\" Subtract \"x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"2y=-x%2B6\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-x%2B6%29%2F%282%29\" Divide both sides by \"2\" to isolate y.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28%28-1%29%2F%282%29%29x%2B%286%29%2F%282%29\" Break up the fraction.\r
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\n" ); document.write( "\n" ); document.write( "\"y=-%281%2F2%29x%2B3\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So the equation \"y=-%281%2F2%29x%2B3\" is now in slope intercept form \"y=mx%2Bb\" where the slope is \"m=-1%2F2\" and the y-intercept is \"b=3\" note: the y-intercept is the point \r
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\n" ); document.write( "\n" ); document.write( "\"2x%2By=9\" Now move onto the second equation.\r
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\n" ); document.write( "\n" ); document.write( "\"y=9-2x\" Subtract \"2x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"y=-2x%2B9\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "So the equation \"y=-2x%2B9\" is now in slope intercept form \"y=mx%2Bb\" where the slope is \"m=-2\" and the y-intercept is \"b=+9\" note: the y-intercept is the point \r
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