document.write( "Question 238584: I need help setting up the following word problem.\r
\n" ); document.write( "\n" ); document.write( "NOT LOOKING FOR THE ANSWER LOOKING FOR THE METHOD PLEASE.\r
\n" ); document.write( "\n" ); document.write( "How much pure acid should be mixed with 6 gallons of a 50% acid solution in order to get an 80% acid solution?\r
\n" ); document.write( "\n" ); document.write( "What I have is wrong I am sure:\r
\n" ); document.write( "\n" ); document.write( ".80=.50(x+6)+(x)
\n" ); document.write( "Any assistance would be greatly appreciated. \n" ); document.write( "
Algebra.Com's Answer #175275 by ankor@dixie-net.com(22740)\"\" \"About 
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How much pure acid should be mixed with 6 gallons of a 50% acid solution in order to get an 80% acid solution?
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\n" ); document.write( "using the decimal equiv of %; pure acid would be 1.0x
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\n" ); document.write( ".50(6) + 1.0x = .80(x+6)
\n" ); document.write( "3 + 1x = .8x + 4.8
\n" ); document.write( "1x - .8x = 4.8 - 3
\n" ); document.write( ".2x = 1.8
\n" ); document.write( "x = \"1.8%2F.2\"
\n" ); document.write( "x = 9
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\n" ); document.write( "Check this in the amt of acid equation
\n" ); document.write( ".5(6) + 1(9) = .8(9 + 6)
\n" ); document.write( "3 + 9 = .8(15)
\n" ); document.write( "12 = 12
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