document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=238584>Question 238584</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help setting up the following word problem.\r<BR>\n" );
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document.write( "NOT LOOKING FOR THE ANSWER LOOKING FOR THE METHOD PLEASE.\r<BR>\n" );
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document.write( "How much pure acid should be mixed with 6 gallons of a 50% acid solution in order to get an 80% acid solution?\r<BR>\n" );
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document.write( "What I have is wrong I am sure:\r<BR>\n" );
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document.write( ".80=.50(x+6)+(x) <BR>\n" );
document.write( "Any assistance would be greatly appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #175274 by </B><A HREF=/tutors/aboutme.mpl?userid=Masaries7><B>Masaries7(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Masaries7><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Masaries7><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=175274\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your question consists of ratios. \r<BR>\n" );
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document.write( " .5(6)/6= 3/6  3 is the gallons of acid. 6 is the total gallons\r<BR>\n" );
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document.write( "To find out how much more gallons of acid you need to obtain 80% acid levels we add our unknown amount to bottom and top of the ratio indicating for the top more acid gallons and for the bottom more total gallons overall. \r<BR>\n" );
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document.write( "3+x/6+x= .8\r<BR>\n" );
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document.write( "Solve for 'x' \r<BR>\n" );
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document.write( "The format for this type of problem is to figure out your initial amounts then set up a ratio equaling the new desired percentage. You must be sure of how the information is applied in the problem for instance had we been adding non-acid solution then there would be no 'x' variable on the top since the ratio we have is  acid gallons/ total gallons. Adding non-acid does not apply to acid. Good tip is to visualize the problem in your mind (if it's possible don't get brain freeze however)  </SPAN>\n" );
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