document.write( "Question 238495: gloria is 4 times as old as theotis. three years ago, she was 7 times as old as he was. how old is each now? \n" ); document.write( "
Algebra.Com's Answer #175268 by Stitch(470)\"\" \"About 
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Let A = Gloria's age
\n" ); document.write( "Let B = Theotis' age\r
\n" ); document.write( "\n" ); document.write( "Equation 1: \"A+=+4B\" Because Gloria is 4 times older than Thesotis
\n" ); document.write( "Equation 2: \"A+-+3+=+7%2A%28B+-+3%29\" We are subtracting 3 from both sides because it was 3 years ago\r
\n" ); document.write( "\n" ); document.write( "In equation 1, we see that A = 4B, therefore we can substitute 4B into Equation 2 for A.
\n" ); document.write( "Equation 2: \"A+-+3+=+7%2A%28B+-+3%29\"
\n" ); document.write( "\"4B+-+3+=+7%2A%28B+-+3%29\" Simplify
\n" ); document.write( "\"4B+-+3+=+7B+-+21\" Add 21 to both sides
\n" ); document.write( "\"21+%2B+4B+-+3+=+7B\" Subtract 4B from both sides
\n" ); document.write( "\"21+-+3+=+7B+-+4B\" Combine like terms
\n" ); document.write( "\"18+=+3B\" Divide both sides by 3
\n" ); document.write( "\"highlight%286+=+B%29\"\r
\n" ); document.write( "\n" ); document.write( "So Theotis is 6.
\n" ); document.write( "To find Gloria' sage plug 6 into equation 1 for A
\n" ); document.write( "Equation 1: \"A+=+4B\"
\n" ); document.write( "\"A+=+4%2A%286%29\"
\n" ); document.write( "\"highlight%28A+=+24%29\"
\n" ); document.write( "Gloria is 24\r
\n" ); document.write( "\n" ); document.write( "You can check your answers by using A=24 & B=6 in equation 2
\n" ); document.write( "Equation 2: \"A+-+3+=+7%2A%28B+-+3%29\"
\n" ); document.write( "\"24+-+3+=+7%2A%286+-+3%29\"
\n" ); document.write( "\"21+=+7%2A%283%29\"
\n" ); document.write( "\"21+=+21\"
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