document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30788>Question 30788</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this. Marion wants to dilute 2 gal of a 28% soap solution to make a 8% solution. How much pure water should she add to make the 8% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17526 by </B><A HREF=/tutors/aboutme.mpl?userid=Fermat><B>Fermat(136)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fermat><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fermat><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17526\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 gall of 28% soap solution<BR>\n" );
document.write( "This comprises of 28% of 2 gall = 0.56 gall of pure soap + 1.44 gal of pure water.<BR>\n" );
document.write( "Let Marion add n gall of pure water.<BR>\n" );
document.write( "Total volume = n+2 gall<BR>\n" );
document.write( "Concentratiuon of soap = 0.56 gall/(n+2) gall and this is to equal 8% = 0.08<BR>\n" );
document.write( "0.56/(n+2) = 0.08<BR>\n" );
document.write( "0.56 = 0.08(n+2)<BR>\n" );
document.write( "0.56 = 0.08n + 0.16<BR>\n" );
document.write( "0.40 = 0.08n<BR>\n" );
document.write( "8n = 40<BR>\n" );
document.write( "n = 5<BR>\n" );
document.write( "Ammount of water to be added is,<BR>\n" );
document.write( "n = 5 gallons<BR>\n" );
document.write( "============= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );