document.write( "Question 238491: how do i find the average of 5/6 4/3 3/4 \r
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document.write( "and how do i solve 5+3/7 2-1/2 \n" );
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Algebra.Com's Answer #175195 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how do i find the average of 5/6 4/3 3/4 \n" ); document.write( "------------------ \n" ); document.write( "Add the three fractions and divide by 3. \n" ); document.write( "----------------- \n" ); document.write( "(5/6) + (4/3) + (3/4) \n" ); document.write( "--- \n" ); document.write( "gcd = 12 \n" ); document.write( "Rewrite each fraction with the gcd as its denominator: \n" ); document.write( "--- \n" ); document.write( "(2*5)/gcd + (4*4)/gcd + (3*3)/gcd \n" ); document.write( "--- \n" ); document.write( "Combine the numerators over the gcd: \n" ); document.write( "[10 + 16 + 9]/gcd \n" ); document.write( "--- \n" ); document.write( "35/12 \n" ); document.write( "============ \n" ); document.write( "To get the average, divide by 3 \n" ); document.write( "[35/12]/3 = 35/36 \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |