document.write( "Question 238484: .10x+.15y=.12
\n" ); document.write( "x+y=100
\n" ); document.write( "

Algebra.Com's Answer #175188 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Multiply the first eq. by 100 to get rid of fractions.
\n" ); document.write( "10x+15y=12
\n" ); document.write( "x+y=100
\n" ); document.write( "Multiply the second eq. by -10 and add to the first to get rid of x.
\n" ); document.write( "10x+15y=12
\n" ); document.write( "-10x-10y=-1000
\n" ); document.write( "5y=-988
\n" ); document.write( "y=-988/5
\n" ); document.write( "Then from
\n" ); document.write( "x+y=100
\n" ); document.write( "x-988/5=500/5
\n" ); document.write( "x=1488/5
\n" ); document.write( "
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