document.write( "Question 238484: .10x+.15y=.12
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document.write( "x+y=100 \n" );
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Algebra.Com's Answer #175188 by Fombitz(32388) You can put this solution on YOUR website! Multiply the first eq. by 100 to get rid of fractions. \n" ); document.write( "10x+15y=12 \n" ); document.write( "x+y=100 \n" ); document.write( "Multiply the second eq. by -10 and add to the first to get rid of x. \n" ); document.write( "10x+15y=12 \n" ); document.write( "-10x-10y=-1000 \n" ); document.write( "5y=-988 \n" ); document.write( "y=-988/5 \n" ); document.write( "Then from \n" ); document.write( "x+y=100 \n" ); document.write( "x-988/5=500/5 \n" ); document.write( "x=1488/5 \n" ); document.write( " |