document.write( "Question 238417: How many degrees are there in an angle that measures 25 degree more than the measure of its complement?\r
\n" ); document.write( "\n" ); document.write( "The measure of the supplement of an angle is 45 degree less than four times the measure of the angle. Find the measure of the angle and its supplement. \n" ); document.write( "
Algebra.Com's Answer #175180 by anantha(86)\"\" \"About 
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sol:
\n" ); document.write( "let the angle be x
\n" ); document.write( "its complement angle=90-x
\n" ); document.write( "according to the problem
\n" ); document.write( "x=25+(90-x)
\n" ); document.write( "90-x transpose to L.H.S side
\n" ); document.write( "x-(90-x)=25
\n" ); document.write( "x-90+x=25
\n" ); document.write( "2x-90=25
\n" ); document.write( "adding 90 on both sides
\n" ); document.write( "2x-90+90=25+90
\n" ); document.write( "2x=115
\n" ); document.write( "dividing by 2 on both sides
\n" ); document.write( "2x/2=115/2
\n" ); document.write( "x=57.5\r
\n" ); document.write( "\n" ); document.write( "sol:
\n" ); document.write( "let the angle be x
\n" ); document.write( "supplement of angle=180-x
\n" ); document.write( "four times the measure of the angle=4x
\n" ); document.write( "according to the problem
\n" ); document.write( "supplement of angle=four times measure of angle-45
\n" ); document.write( "180-x=4x-45
\n" ); document.write( "transpose 45 on L.H.S side and x on R.H.S side
\n" ); document.write( "180+45=4x+x
\n" ); document.write( "225=5x
\n" ); document.write( "dividing both sides by 5
\n" ); document.write( "225/5=5x/5
\n" ); document.write( "45=x
\n" ); document.write( "supplement of angle=180-45=135\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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