document.write( "Question 238426: x^(2n+1)-2x^(n+1)+x \n" ); document.write( "
Algebra.Com's Answer #175179 by jsmallt9(3758)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Is there something missing? Without an equals sign this is just an expression. And all you can do with an expression is simplify it or factor it. \n" ); document.write( "Since your expression does not simplify any farther all we can do is factor it. To see how to factor it I am going to use the property of exponents, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "We can now see that x is a common factor which we can factor out: \n" ); document.write( " \n" ); document.write( "And now we can factor the second factor as a perfect square trinomial. (It may be easier to see this as a perfect square trinomial if we use the property of exponents, \n" ); document.write( " \n" ); document.write( "This fits the perfect square trinomial pattern, \n" ); document.write( " \n" ); document.write( "If there was an \"= 0\" missing in the original equation, we would use factoring to solve it. We would now have: \n" ); document.write( " \n" ); document.write( "And this would be true only if \n" ); document.write( " \n" ); document.write( "Without knowing n we will not be able to find all the solutions to the second equation. But one solution is x = 1. \n" ); document.write( "So, if the problem was \n" ); document.write( "x = 0 or x = 1\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |