document.write( "Question 238389: can you tell me how to convert a parabola into an equation... x intercepts are (3,0) and (13,0) how do i find the vertex if thats all the info i have... \n" ); document.write( "
Algebra.Com's Answer #175171 by Theo(13342) You can put this solution on YOUR website! x-intercepts are (3,0) and (13,0)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the roots of your equation are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 3 \n" ); document.write( "x = 13\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this was derived from:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x-3 = 0 \n" ); document.write( "x - 13 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that came from:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-3) * (x-13) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply these factors together to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 16x + 39 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's your quadratic equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it's in standard form.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can find the vertex from that form by doing the following:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "standard form of a quadratic equation is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "ax^2 + bx + c = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 16x + 39 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = 1 \n" ); document.write( "b = -16 \n" ); document.write( "c = 39\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x value of the vertex is given by the equation x = -b/2a.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 16/2 = 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y value of the vertex is given by the equation y = f(-b/2a).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this means y = f(8) which means you replace x with 8 in your equation and solve for y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation is y = x^2 - 16x + 39\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace x with 8 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 64 - 128 + 39 = -25.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your vertex is (x,y) = (8,-25)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a graph of your equation looks like:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you are really just working backwards.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you are given the equation, you find the roots.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you are given the roots, you find the equation by backtracking how you find the roots.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |