document.write( "Question 238342: my question is, y=-3x-4 and line J is perpindicular to the equation, but also passes through point (1,1) what is the answer? \n" ); document.write( "

Algebra.Com's Answer #175147 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
If a line has slope = $\"m\"$ , then
\n" ); document.write( "any line perpendicular to it will have
\n" ); document.write( "slope = $\"-1%2Fm\"$
\n" ); document.write( " $\"y+=+-3x+-+4\"$
\n" ); document.write( " $\"m+=+-3\"$
\n" ); document.write( "Perpendicular line J, $\"m%5BJ%5D+=+-%281%2F%28-3%29%29\"$
\n" ); document.write( " $\"m%5BJ%5D+=+1%2F3\"$
\n" ); document.write( "So far I know line J has the form
\n" ); document.write( " $\"y+=+%281%2F3%29x+%2B+b\"$ . I know it goes through (1,1),
\n" ); document.write( "so I can just plug these values for $\"x\"$ and $\"y\"$
\n" ); document.write( "back into the equation for J
\n" ); document.write( " $\"1+=+%281%2F3%29%2A1+%2B+b\"$
\n" ); document.write( " $\"b+=+1+-+1%2F3\"$
\n" ); document.write( " $\"b+=+2%2F3\"$
\n" ); document.write( "The equation for J is $\"y+=+%281%2F3%29x+%2B+2%2F3\"$
\n" ); document.write( "I'll plot the 2 lines to check my work
\n" ); document.write( " $\"+graph%28+400%2C+500%2C+-5%2C+5%2C+-5%2C+5%2C+-3x+-+4%2C+%281%2F3%29x+%2B+2%2F3%29+\"$
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