document.write( "Question 238270: The directions are Solve each system by elimination. Check your answers. The first problem is
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document.write( " x-y+z=-1 x+y+3z=-3 2x-y+2z=0
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document.write( "I've tried this like 15 times and cannot figure it out. Most of the time I would check what I got and it would be 1 instead of -1 or 3 instead of -3... I know how to do them I think. But I just can't get it. \n" );
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Algebra.Com's Answer #175100 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve each system by elimination. Check your answers. The first problem is \n" ); document.write( "x-y+z=-1 \n" ); document.write( "x+y+3z=-3 \n" ); document.write( "2x-y+2z=0 \n" ); document.write( "--------------------- \n" ); document.write( "Subtract 1st from the 2nd; \n" ); document.write( "Subtract 2 times the 1st from the 3rd. \n" ); document.write( "----------- \n" ); document.write( "x-y+z=-1 \n" ); document.write( "0x+2y+2z=-2 \n" ); document.write( "0x+y+0z=2 \n" ); document.write( "----------------- \n" ); document.write( "Solve the 3rd Eq. for y: y = 2 \n" ); document.write( "-------------------------- \n" ); document.write( "Substitute y=2 into the 2nd equation and solve for \"z\": \n" ); document.write( "2*2 + 2z = -2 \n" ); document.write( "2Z = -6 \n" ); document.write( "z = -3 \n" ); document.write( "------------ \n" ); document.write( "Substitute into x-y+z=-1 and solve for \"x\" \n" ); document.write( "x - 2 - 3 = -1 \n" ); document.write( "x = 4 \n" ); document.write( "=================================== \n" ); document.write( "Solution: \n" ); document.write( "x = 4 \n" ); document.write( "y = 2 \n" ); document.write( "z = -3 \n" ); document.write( "00000000000000000000000000000000000 \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |