document.write( "Question 238270: The directions are Solve each system by elimination. Check your answers. The first problem is
\n" ); document.write( " x-y+z=-1 x+y+3z=-3 2x-y+2z=0
\n" ); document.write( "I've tried this like 15 times and cannot figure it out. Most of the time I would check what I got and it would be 1 instead of -1 or 3 instead of -3... I know how to do them I think. But I just can't get it.
\n" ); document.write( "

Algebra.Com's Answer #175100 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Solve each system by elimination. Check your answers. The first problem is
\n" ); document.write( "x-y+z=-1
\n" ); document.write( "x+y+3z=-3
\n" ); document.write( "2x-y+2z=0
\n" ); document.write( "---------------------
\n" ); document.write( "Subtract 1st from the 2nd;
\n" ); document.write( "Subtract 2 times the 1st from the 3rd.
\n" ); document.write( "-----------
\n" ); document.write( "x-y+z=-1
\n" ); document.write( "0x+2y+2z=-2
\n" ); document.write( "0x+y+0z=2
\n" ); document.write( "-----------------
\n" ); document.write( "Solve the 3rd Eq. for y: y = 2
\n" ); document.write( "--------------------------
\n" ); document.write( "Substitute y=2 into the 2nd equation and solve for \"z\":
\n" ); document.write( "2*2 + 2z = -2
\n" ); document.write( "2Z = -6
\n" ); document.write( "z = -3
\n" ); document.write( "------------
\n" ); document.write( "Substitute into x-y+z=-1 and solve for \"x\"
\n" ); document.write( "x - 2 - 3 = -1
\n" ); document.write( "x = 4
\n" ); document.write( "===================================
\n" ); document.write( "Solution:
\n" ); document.write( "x = 4
\n" ); document.write( "y = 2
\n" ); document.write( "z = -3
\n" ); document.write( "00000000000000000000000000000000000
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" ); document.write( "
\n" );