document.write( "Question 238183: will has $2.05 in dimes and quarters.He has 4 more quarters than dimes.Find the number he has of each kind of coin \n" ); document.write( "
Algebra.Com's Answer #175097 by checkley77(12844) ![]() You can put this solution on YOUR website! D=Q+4 \n" ); document.write( ".25Q+.10D=2.05 \n" ); document.write( ".25Q+.10(Q+4)=2.05 \n" ); document.write( ".25Q+.10Q+.4=2.05 \n" ); document.write( ".35Q=2.05-.4 \n" ); document.write( ".35Q=1.65 \n" ); document.write( "Q=1.65/.35 \n" ); document.write( "Q=4.714 NUMBER OF QUARTERS. \n" ); document.write( "D=4.714+4 \n" ); document.write( "D=8.714 DIMES NUMBER OF. \n" ); document.write( "PROOF: \n" ); document.write( ".25*4.714+.10*8.714=2.05 \n" ); document.write( "1.1785+.8714=2.05 \n" ); document.write( "205~205 \n" ); document.write( "CAN'T HAVE PARTIAL COINS. THERE MUST BE A MISTAKE IN THE COIN COUNT OR THE TOTAL AMOUNT OF THE COINS. \n" ); document.write( " |