document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=238270>Question 238270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The directions are Solve each system by elimination. Check your answers. The first problem is <BR>\n" );
document.write( "               x-y+z=-1      x+y+3z=-3   2x-y+2z=0<BR>\n" );
document.write( "I've tried this like 15 times and cannot figure it out. Most of the time I would check what I got and it would be 1 instead of -1 or 3 instead of -3... I know how to do them I think. But I just can't get it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #175093 by </B><A HREF=/tutors/aboutme.mpl?userid=alicealc><B>alicealc(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alicealc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=175093\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first, eliminate y from the 1st and 2nd equation:<BR>\n" );
document.write( "x - y + z  = -1<BR>\n" );
document.write( "x + y + 3z = -3<BR>\n" );
document.write( "--------------- (+)<BR>\n" );
document.write( "2x + 4z = -4<BR>\n" );
document.write( "divide both sides by 2:<BR>\n" );
document.write( "x + 2z = -2\r<BR>\n" );
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document.write( "then, eliminate y from the 1st and 3rd equation:<BR>\n" );
document.write( " x - y + z  = -1<BR>\n" );
document.write( "2x - y + 2z =  0<BR>\n" );
document.write( "----------------- (-)<BR>\n" );
document.write( "-x - z = -1 <BR>\n" );
document.write( "multiply both sides by (-1)<BR>\n" );
document.write( "x + z = 1\r<BR>\n" );
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document.write( "then, eliminate x from both results:<BR>\n" );
document.write( "x + 2z = -2<BR>\n" );
document.write( "x +  z =  1<BR>\n" );
document.write( "------------ (-)<BR>\n" );
document.write( "z = -3\r<BR>\n" );
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document.write( "subtitute z = -3 into x + z = 1<BR>\n" );
document.write( "x + (-3) = 1<BR>\n" );
document.write( "x = 1 + 3 = 4\r<BR>\n" );
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document.write( "substitute x = 4 and z = -3 into the 1st equation:<BR>\n" );
document.write( "x - y + z = -1<BR>\n" );
document.write( "4 - y + (-3) = -1<BR>\n" );
document.write( "1 - y = -1<BR>\n" );
document.write( "1 + 1 = y<BR>\n" );
document.write( "2 = y\r<BR>\n" );
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document.write( "so,the result will be: x = 4, y = 2, z = -3<BR>\n" );
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