document.write( "Question 238189: How many liters of 20% alcohol solution and 10% alcohol solution must be mixed to obtain 50 liters of a 12% alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #175090 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .20x+.10(50-x)=.12*50 \n" ); document.write( ".20x+5-.10x=6 \n" ); document.write( ".10x=6-5 \n" ); document.write( ".10x=1 \n" ); document.write( "x=1/.1 \n" ); document.write( "x=10 liters of 20% alcohol is used. \n" ); document.write( "50-10=40 liters of 10% alcohol is used. \n" ); document.write( "Proof: \n" ); document.write( ".20*10+.10*40=.12*50 \n" ); document.write( "2+4=6 \n" ); document.write( "6=6 \n" ); document.write( " \n" ); document.write( " |