document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=238264>Question 238264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a triangle has a perimeter of 54 inches. find the length of the three sides if one side is 10 inches longer than the smallest and the third side is twice the smallest. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #175084 by </B><A HREF=/tutors/aboutme.mpl?userid=alicealc><B>alicealc(293)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alicealc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=175084\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first side (smallest) = x<BR>\n" );
document.write( "second side = 10 + x<BR>\n" );
document.write( "third side = 2x\r<BR>\n" );
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document.write( "perimeter = 54<BR>\n" );
document.write( "x + 10 + x + 2x =54<BR>\n" );
document.write( "4x + 10 = 54<BR>\n" );
document.write( "4x = 54 - 10<BR>\n" );
document.write( "4x = 44<BR>\n" );
document.write( "x = 44/4<BR>\n" );
document.write( "x = 11\r<BR>\n" );
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document.write( "so, the three sides of the triangle will be: 11 inches, 21 inches,and 22 inches </SPAN>\n" );
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