document.write( "Question 238193: how do you find the b in y=mx+b \n" ); document.write( "
Algebra.Com's Answer #175030 by Theo(13342)\"\" \"About 
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the standard form is y = mx + b where m is the slope and b is the y-intercept.\r
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\n" ); document.write( "\n" ); document.write( "assume you are given the slope and one point on the line.\r
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\n" ); document.write( "\n" ); document.write( "let the slope = 2\r
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\n" ); document.write( "\n" ); document.write( "let the point = (3,5)\r
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\n" ); document.write( "\n" ); document.write( "the standard form of y = mx + b becomes y = 2x + b\r
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\n" ); document.write( "\n" ); document.write( "now you take the point (x,y) = (3,5) that is on the line (has to be on the line) and replace x and y in the equation with it.\r
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\n" ); document.write( "\n" ); document.write( "the equation becomes 5 = 2*3 + b\r
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\n" ); document.write( "\n" ); document.write( "then you solve for b.\r
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\n" ); document.write( "\n" ); document.write( "in this case b = 5-1 = -1\r
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\n" ); document.write( "\n" ); document.write( "your equation becomes y = 2x - 1\r
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\n" ); document.write( "\n" ); document.write( "graph of that equation looks like:\r
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\n" ); document.write( "\n" ); document.write( "\"graph+%28400%2C400%2C-5%2C5%2C-5%2C5%2C2x-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "b is the y intercept which is the value of y when x = 0 which is -1.\r
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\n" ); document.write( "\n" ); document.write( "the graph confirms that.\r
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\n" ); document.write( "\n" ); document.write( "the slope is 2 which means that everytime x increases 1 unit, y increases 2 units.\r
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\n" ); document.write( "\n" ); document.write( "that can be seen on the graph as well.\r
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\n" ); document.write( "\n" ); document.write( "when x = 0, y = -1.\r
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\n" ); document.write( "\n" ); document.write( "when x = 1, y = 1\r
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\n" ); document.write( "\n" ); document.write( "when = 2, y = 3\r
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\n" ); document.write( "\n" ); document.write( "etc.\r
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