document.write( "Question 238110: please show how to solve t squared minus seventeen equals 2t \n" ); document.write( "
Algebra.Com's Answer #174984 by Theo(13342)![]() ![]() You can put this solution on YOUR website! t^2 - 17 = 2t\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 2t from both sides of the equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "t^2 - 2t - 17 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's a quadratic equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it doesn't look like it will factor, so use the quadratic formula to solve it.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the quadratic formula is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = -b +/- sqrt(b^2-4ac)/2a\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "standard form of the quadratic equation is ax^2 + bx + c\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in your equation of t^2 - 2t - 17 = 0, replace t with x to make it:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 2x - 17 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = coefficient of x^2 term = 1 \n" ); document.write( "b = coefficient of x term = -2 \n" ); document.write( "c = constant term = -17\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substitute in quadratic formula of:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = -b +/- sqrt(b^2-4ac)/2a to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this becomes\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 5.242640687 or x = -3.242640687\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to confirm these values are true, substitute in the original equation and solve.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "both values substituted and confirmed the original equations so the answers are good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a graph of this equation looks like:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |