document.write( "Question 30746: A log 78 feet long is to be cut into 3 pieces varying lengths. The longest piece is to be 4 times the length of the shortest piece and the middle size piece is to be 6 feet less than twice the length of the shortest piece. How long is the shortest piece. \n" ); document.write( "
Algebra.Com's Answer #17496 by Paul(988)\"\" \"About 
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Let the shortest piece be x
\n" ); document.write( "Let the middle piece be 2x-6
\n" ); document.write( "Let the longest piece be 4x
\n" ); document.write( "Equation:
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(x)+(2x-6)+(4x)=78
\n" ); document.write( "7x=84
\n" ); document.write( "x=12\r
\n" ); document.write( "\n" ); document.write( "2(12)-6=18
\n" ); document.write( "4(12)=48\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hence, the 3 pieces are 12ft, 18ft, and 48ft.
\n" ); document.write( "Paul. \n" ); document.write( "
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