document.write( "Question 30759: I have 4 spinner and there are 3 colours on the spinner red, blue and orange. If i spin the spinner twice what is the probability that i get all the same colour on the first spin and all the same colour on the second spin. \n" ); document.write( "
Algebra.Com's Answer #17495 by longjonsilver(2297)\"\" \"About 
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Assuming all the spinners are unbiased and the same and that P(red)=P(blue)=P(orange), then we have:\r
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\n" ); document.write( "\n" ); document.write( "P(rad) = P(blue) = P(orange) = 1/3\r
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\n" ); document.write( "\n" ); document.write( "On first spin of the 4 tops:\r
\n" ); document.write( "\n" ); document.write( "P(all red) = (1/3) * (1/3) * (1/3) * (1/3)
\n" ); document.write( "P(all red) = (1/81)\r
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\n" ); document.write( "\n" ); document.write( "Similarly, P(all blue) = (1/81) and P(all orange) = (1/81)\r
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\n" ); document.write( "\n" ); document.write( "So, P(all 4 tops are the same colour) = (1/81) + (1/81) + (1/81)
\n" ); document.write( "P(all 4 tops are the same colour) = (3/81)
\n" ); document.write( "P(all 4 tops are the same colour) = 1/27\r
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\n" ); document.write( "\n" ); document.write( "Now, spinning the top a second time produces the same result... the 2 situations are independent, since they do not affect each other.\r
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\n" ); document.write( "\n" ); document.write( "So, P(4 same colour AND then 4 same colour again) = (1/27) * (1/27)
\n" ); document.write( "--> 1/729\r
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\n" ); document.write( "\n" ); document.write( "jon.
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