document.write( "Question 238019: Mary is twice Wang's age & Kat is 2 years younger the Wang. The sum total of their ages is 46. How old is each person? \n" ); document.write( "
Algebra.Com's Answer #174938 by anantha(86)![]() ![]() ![]() You can put this solution on YOUR website! sol: \n" ); document.write( "let Wang's age be x \n" ); document.write( "Mary is twice Wnag's=2*x \n" ); document.write( "kat is 2 years younger the wang=x-2 \n" ); document.write( "according to the problem \n" ); document.write( "sum of their ages=46 \n" ); document.write( "x+2x+x-2=46 \n" ); document.write( "4x-2=46 \n" ); document.write( "adding 2 on both sides \n" ); document.write( "4x-2+2=46+2 \n" ); document.write( "4x=48 \n" ); document.write( "dividing by 4 on both sides \n" ); document.write( "4x/4=48/4 \n" ); document.write( "x=12 \n" ); document.write( "Wang's age=12 years \n" ); document.write( "Mary age=2*Wang's age=2*12=24 years \n" ); document.write( "Kat age=Wang's age-2=12-2=10 years \n" ); document.write( "check: \n" ); document.write( "sum of their ages=46 \n" ); document.write( "Wang's age+Mary age+Kat age=12+24+10=46 \n" ); document.write( "L.H.S=R.H.S\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |