document.write( "Question 238004: log2x=log3 + log(x-4) \n" ); document.write( "

Algebra.Com's Answer #174922 by nerdybill(7384) $\"\"$ $\"About$

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log2x=log3 + log(x-4)
\n" ); document.write( " log 2x = log 3(x-4)
\n" ); document.write( " 2x = 3(x-4)
\n" ); document.write( " 2x = 3x-12
\n" ); document.write( " -x = -12
\n" ); document.write( " x = 12
\n" ); document.write( "
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