document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=237999>Question 237999</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Bacteria grow by cell division. If each cell divides into 2 in every 2 minutes how many cells will exist after 32 minutes? Assume there was only one cell at the beginning </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174919 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174919\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     Bacteria grow by cell division. If each cell divides into 2 in every 2 minutes how many cells will exist after 32 minutes? Assume there was only one cell at the beginning<BR>\n" );
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document.write( "Apply exponential growth equation:<BR>\n" );
document.write( "A(t) = Pe^(rt)<BR>\n" );
document.write( "where<BR>\n" );
document.write( "A(t) is amount at time t (2)<BR>\n" );
document.write( "P is the initial amount (1)<BR>\n" );
document.write( "r is rate of growth (unknown)<BR>\n" );
document.write( "t is time (2)<BR>\n" );
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document.write( "Finding r:<BR>\n" );
document.write( "A(t) = Pe^(rt)<BR>\n" );
document.write( "2 = 1e^(2r)<BR>\n" );
document.write( "ln(2) = 2r<BR>\n" );
document.write( "ln(2)/2 = r<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Cells at 32 minutes:<BR>\n" );
document.write( "A(32) = 1e^(ln(2)/2 * 32)<BR>\n" );
document.write( "A(32) = e^(ln(2) * 16)<BR>\n" );
document.write( "A(32) = 65536 cells </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );