document.write( "Question 237931: Please help. Can someone please show me the steps so I can understand how to do this?
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document.write( "Solve for a
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document.write( "a^2+a-42=0\r
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document.write( "Factor
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document.write( "72-17s+s^2 \n" );
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Algebra.Com's Answer #174898 by Alan3354(69443) You can put this solution on YOUR website! Solve for a \n" ); document.write( "a^2+a-42=0 \n" ); document.write( "Factor it \n" ); document.write( "(a + 7)*(a - 6) = 0 \n" ); document.write( "a = -7, a = 6 \n" ); document.write( "-------------- \n" ); document.write( "Factor \n" ); document.write( "72-17s+s^2 \n" ); document.write( "= s^2 - 17s + 72 It's a good idea to put it in descending order. \n" ); document.write( "---------------- \n" ); document.write( "The coefficents of the x terms are both 1. \n" ); document.write( "So it will be: \n" ); document.write( "(x ± a)*(x ± b) \n" ); document.write( "The two numbers multiply to 72, a*b = 72 \n" ); document.write( "The 72 is positive, so they have the same sign. \n" ); document.write( "The s term is negative, so a and b are negative. \n" ); document.write( "--> (x - a)*(x - b) \n" ); document.write( "ab = 72 \n" ); document.write( "a+b = -17 \n" ); document.write( "--------- \n" ); document.write( "Look at the factors of 72 and the sum: \n" ); document.write( "1 and 72 = 73 \n" ); document.write( "2 and 36 = 38 \n" ); document.write( "3 and 24 = 27 \n" ); document.write( "4 and 18 = 22 \n" ); document.write( "6 and 12 = 18 \n" ); document.write( "8 and 9 = 17 That's it. \n" ); document.write( "72-17s+s^2 = (s - 8)*(s - 9) \n" ); document.write( " \n" ); document.write( " |