document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30737>Question 30737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to solve the equation and I am very confused.  Help!!\r<BR>\n" );
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document.write( "   14 over b-6 = 1/2 + 6 over b-8\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17489 by </B><A HREF=/tutors/aboutme.mpl?userid=ikdeep><B>ikdeep(226)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikdeep><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikdeep><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17489\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "   14 over b-6 = 1/2 + 6 over b-8\r<BR>\n" );
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document.write( "or it is written as \r<BR>\n" );
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document.write( "   14 / b-6 = 1/2 + 6 / b-8\r<BR>\n" );
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document.write( "on taking LCM on RHS we get..\r<BR>\n" );
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document.write( "14 / b-6 =  ( b-8 + 12) / 2(b-8)\r<BR>\n" );
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document.write( "14 / b-6 =   b + 4 / 2b -16 \r<BR>\n" );
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document.write( "cross multiply and we get..\r<BR>\n" );
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document.write( "14(2b-16) = (b+4)(b-6)\r<BR>\n" );
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document.write( "solving brackets on both side give us ...\r<BR>\n" );
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document.write( "28b - 224 = b^2 - 2b -24\r<BR>\n" );
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document.write( "putting together the like variables ,,,\r<BR>\n" );
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document.write( "0 = b^2 - 2b -28b -24 + 224\r<BR>\n" );
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document.write( "0 =  b^2 - 30b + 200\r<BR>\n" );
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document.write( "Here you must know how we make factors i.e. splitting of the middle term...if you might not know then please contact me again and I will explain to you...\r<BR>\n" );
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document.write( "0 = b^2 -( 20 -10)b + 200\r<BR>\n" );
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document.write( "0 = b^2 - 20b - 10b + 200\r<BR>\n" );
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document.write( "taking common from first two i.e. b^2 - 20b and last two i.e. 10b + 200<BR>\n" );
document.write( "variables...we get \r<BR>\n" );
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document.write( "0 = b(b-20) -10(b-20)\r<BR>\n" );
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document.write( "0= (b-10)(b-20)\r<BR>\n" );
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document.write( "hope this will help you \r<BR>\n" );
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document.write( "Please feel free to revert back for any further queries. </SPAN>\n" );
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