document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30732>Question 30732</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measure of an angle if it's supplement measures 15 degrees less than 4 times it's complement </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17487 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the measure of an angle if it's supplement measures 15 degrees less than 4 times it's complement<BR>\n" );
document.write( "Let the required angle be A degrees<BR>\n" );
document.write( "Let its supplement be S degrees <BR>\n" );
document.write( "and complement be C degrees.<BR>\n" );
document.write( "Then we have <BR>\n" );
document.write( "A+S = 180 ----(1)And <BR>\n" );
document.write( "A+C = 90 ----(2)<BR>\n" );
document.write( "supplement measures 15 degrees less than 4 times it's complement<BR>\n" );
document.write( "That is S measures 15 less than 4C<BR>\n" );
document.write( "That is  S = 4C-15  ----(3)<BR>\n" );
document.write( "Now (1) - (2) gives<BR>\n" );
document.write( "(A-A) +(S-C) = 180-90<BR>\n" );
document.write( "0 +(S-C) = 90<BR>\n" );
document.write( "(S-C) = 90<BR>\n" );
document.write( "That is S = 90+C ----(4)<BR>\n" );
document.write( "From (3) and (4)<BR>\n" );
document.write( "4C-15 = 90+C<BR>\n" );
document.write( "4C-C =90+15<BR>\n" );
document.write( "3C = 105<BR>\n" );
document.write( "C = 105/3 = 35<BR>\n" );
document.write( "Putting C = 35 in (2)<BR>\n" );
document.write( "A+C = 90<BR>\n" );
document.write( "A+35= 90<BR>\n" );
document.write( "A =90-35 = 55<BR>\n" );
document.write( "Answer: A = 55 degrees. That is the required angle is 55 degrees<BR>\n" );
document.write( "Verification:From (1) S = 180-A = 180-55 = 125 and <BR>\n" );
document.write( "From (3) S = 4C-15 = 4X35 - 15 = 140-15 = 125 which is correct from above<BR>\n" );
document.write( "Therefore our angle A is correct<BR>\n" );
document.write( "Note: Why did we do (1)-(2)?<BR>\n" );
document.write( "Answer: To get an equation in S and C so that <BR>\n" );
document.write( "we can make it converse with (3) which is given in S and C<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );