document.write( "Question 30729: a boat travels upstream for 32 miles in 2 hours.return trip at same constant speed with the same current only taking 1 hour and 36 mins.what is the speed of the boat and the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #17484 by ikdeep(226)\"\" \"About 
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upstream distance = 32 miles
\n" ); document.write( "upstream time = 2 hours
\n" ); document.write( "upstream speed = ?
\n" ); document.write( " (applying the formula.. speed = distance / time)\r
\n" ); document.write( "\n" ); document.write( " = 32/2 \r
\n" ); document.write( "\n" ); document.write( " = 16 miles/hour\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "down stream distance = 36 miles
\n" ); document.write( "down stream time = 1 hours
\n" ); document.write( "down stream speed = ?
\n" ); document.write( " (applying the formula ..speed = distance / time)\r
\n" ); document.write( "\n" ); document.write( " = 36/1 \r
\n" ); document.write( "\n" ); document.write( " = 36 miles / hour\r
\n" ); document.write( "\n" ); document.write( "Now speed of boat in still water = (downstream speed + upstream speed)/2\r
\n" ); document.write( "\n" ); document.write( "= (36 + 16)/2\r
\n" ); document.write( "\n" ); document.write( "= 52 / 2 \r
\n" ); document.write( "\n" ); document.write( "= 26 miles /hour\r
\n" ); document.write( "\n" ); document.write( "Now speed of current = (downstream speed - upstream speed)/2\r
\n" ); document.write( "\n" ); document.write( " = (36 - 16) /2\r
\n" ); document.write( "\n" ); document.write( " = 20/2 \r
\n" ); document.write( "\n" ); document.write( " = 10 miles /hour
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