document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30743>Question 30743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> David has a landscaping business, he is going to be placing a circular border of diameter 10 feet around a tree.  Inside he will plant flowers. Find the circumference of the border. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17483 by </B><A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><B>sdmmadam@yahoo.com(530)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sdmmadam@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17483\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Diameter length of the given circle = 10 feet<BR>\n" );
document.write( "And diameter of a circle = 2 times radius of the circle<BR>\n" );
document.write( "Therefore  10 = 2r where r is the radius of the circle<BR>\n" );
document.write( "That is 2r = 10<BR>\n" );
document.write( "dividing by 2, we get<BR>\n" );
document.write( "r = 5<BR>\n" );
document.write( "Therefore the radius of the flower circle = 5 feet<BR>\n" );
document.write( "Circumference of the circle by formula<BR>\n" );
document.write( "= 2(pi)r<BR>\n" );
document.write( "= 2X(22/7)X5<BR>\n" );
document.write( "=220/7<BR>\n" );
document.write( "=31.4285..<BR>\n" );
document.write( "Therefore circumference of the circle is 31.43 feet approximately<BR>\n" );
document.write( " </SPAN>\n" );
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