document.write( "Question 237751: Log x = 2.5 \n" ); document.write( "
Algebra.Com's Answer #174800 by stanbon(75887) ![]() You can put this solution on YOUR website! Log x = 2.5 \n" ); document.write( "---- \n" ); document.write( "That means 10^2.5 = x \n" ); document.write( "x = 10^2*10^(0.5) \n" ); document.write( "--- \n" ); document.write( "x = 100*sqrt(10) \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |