document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=237628>Question 237628</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If sin p= 2/3 and p is greater than 90 and smaller than 180 <BR>\n" );
document.write( "then what is tan p equal to?<BR>\n" );
document.write( "Please solve and explain.<BR>\n" );
document.write( "Thanks<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174746 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174746\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If sin p= 2/3 and p is greater than 90 and smaller than 180 <BR>\n" );
document.write( "then what is tan p equal to?<BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "If sin(p) = 2/3 , y = 2 and r = 3<BR>\n" );
document.write( "Then x = sqrt(r^2-y^2) = sqrt(9-4) = sqrt(5)<BR>\n" );
document.write( "----------------------------------------------<BR>\n" );
document.write( "tan(p) = ?<BR>\n" );
document.write( "tan(p) = y/x<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Note: y is positive in the 2nd Quadrant and x is negative<BR>\n" );
document.write( "---<BR>\n" );
document.write( "So you get tan(p) = 2/(-sqrt(5)) = -(2sqrt(5)/5 or (-2/5)sqrt(5)<BR>\n" );
document.write( "===============================================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );