document.write( "Question 237569: c=5/9(f-32), for f \n" ); document.write( "
Algebra.Com's Answer #174701 by nyc_function(2741)\"\" \"About 
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Given c = 5/9(f-32), solve for f.\r
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\n" ); document.write( "\n" ); document.write( "c=5/9(f-32) can also be written as c = 5(f - 32)/9.\r
\n" ); document.write( "\n" ); document.write( "Multiply each side by 9.\r
\n" ); document.write( "\n" ); document.write( "That gives us 9c = 5(f - 32).\r
\n" ); document.write( "\n" ); document.write( "Apply distributive rule on the right side.\r
\n" ); document.write( "\n" ); document.write( "9c = 5f - 160\r
\n" ); document.write( "\n" ); document.write( "Add 160 to the left side.\r
\n" ); document.write( "\n" ); document.write( "9c + 160 = 5f\r
\n" ); document.write( "\n" ); document.write( "Lastly, divide both sides 5.\r
\n" ); document.write( "\n" ); document.write( "(9c + 160)/5 = f\r
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