document.write( "Question 30752: { { { 5/p^2 - 5/q^2 / 1/p + 1/q } } } \n" ); document.write( "
Algebra.Com's Answer #17468 by ikdeep(226)![]() ![]() You can put this solution on YOUR website! { { { 5/p^2 - 5/q^2 / 1/p + 1/q } } }\r \n" ); document.write( "\n" ); document.write( "there is no need for the brackets ,,so remove them and we get ...\r \n" ); document.write( "\n" ); document.write( "= 5/p^2 - 5/q^2 / 1/p + 1/q \r \n" ); document.write( "\n" ); document.write( "thaking LCM a from frist two i.e. 5/p^2 - 5/q^2 and last two i.e. 1/p + 1/q \n" ); document.write( " variables we get ...\r \n" ); document.write( "\n" ); document.write( "=(5q^2 - 5p^2)/p^2q^2 / (q+p)/pq\r \n" ); document.write( "\n" ); document.write( " on solving the equation we get.. \n" ); document.write( "=(5q^2 - 5p^2)/[pq *(q+p)]\r \n" ); document.write( "\n" ); document.write( "taking commom from the numerator we get ...\r \n" ); document.write( "\n" ); document.write( "= 5( q^2 - p^2)/ [pq * (q+p)]\r \n" ); document.write( "\n" ); document.write( "now on applying formula a^2 - b^2 = (a+b)(a-b) we get... \r \n" ); document.write( "\n" ); document.write( "= 5(q+p)(q-p)/ [pq * (q+p)]\r \n" ); document.write( "\n" ); document.write( "[ (q+p) is common in both denominator and numerator so it will de eliminated ]and we get...\r \n" ); document.write( "\n" ); document.write( "= 5(q-p) / pq\r \n" ); document.write( "\n" ); document.write( "= (5q - 5p )/ pq\r \n" ); document.write( "\n" ); document.write( "hope this will help you...\r \n" ); document.write( "\n" ); document.write( "if you are unable to understand the problem ,,contact at my link and I will send you the handwritten scanned copy for better understanding.\r \n" ); document.write( "\n" ); document.write( "Please feel free to revert back for any further queries.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |