document.write( "Question 237533: this is a \"solving systems of equations using substitution\" question. I tried to solve it using a negative and a positive number but i cant. i've been stuck on this question for 30 minutes. Please help me as soon as possible.\r
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document.write( "2x-3y=6
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document.write( "x+y=12\r
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document.write( "*when you solve x+y=12, does it become y=x-12 or y=x+12?
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document.write( "*also, when you plug in for y ---> 2x-3(x-12)=6, does it become 2x-3x+12=6 or 2x-3x-12=6 or 2x+3x+12=6 or 2x+3x-12=6? \n" );
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Algebra.Com's Answer #174665 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2x-3y=6 \n" ); document.write( "x+y=12 \n" ); document.write( "*when you solve x+y=12, does it become y=x-12 or y=x+12? \n" ); document.write( "*also, when you plug in for y ---> 2x-3(x-12)=6, does it become 2x-3x+12=6 or 2x-3x-12=6 or 2x+3x+12=6 or 2x+3x-12=6? \n" ); document.write( "---------------------------- \n" ); document.write( "Solve the 2nd equation for \"y\": \n" ); document.write( "y = -x + 12 \n" ); document.write( "---- \n" ); document.write( "Substitute that into the 1st equation and solve for \"x\": \n" ); document.write( "2x -3(-x+12) = 6 \n" ); document.write( "2x + 3x - 36 = 6 \n" ); document.write( "5x = 42 \n" ); document.write( "x = 42/5 = 8 2/5 \n" ); document.write( "----------------------- \n" ); document.write( "Substitute that into y = -x +12 to get: \n" ); document.write( "y = -(42/5)+(60/5) \n" ); document.write( "y = 18/5 = 3 3/5 \n" ); document.write( "--------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |