document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=237507>Question 237507</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 7:00 A.M. Joe starts jogging at 6mi/h. At 7:10 A.M. Ken starts off after him. How fast much ken run in order to overtake him at 7:30 A.M. ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174650 by </B><A HREF=/tutors/aboutme.mpl?userid=College+Student><B>College Student(505)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=College+Student><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=College+Student><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174650\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Joe runs at a pace of 6 miles/hour ...same as 3 miles/30 minutes.<BR>\n" );
document.write( "Ken must run the same distance, but in less time.  <BR>\n" );
document.write( "Which means he must run 3 miles/20 minutes ... same as 9 miles/hour to catch up with Joe at 7:30 AM. </SPAN>\n" );
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