document.write( "Question 30716: Can you please help me with this one? I think it's linear. ** A rectangle has a length 5 inches longer than its width. If both the length and the width of the rectangle are increased by 3 inches, the area of the rectangle is increased by 36 square inches. Find the original dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #17463 by venugopalramana(3286)\"\" \"About 
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Can you please help me with this one? I think it's linear. ** A rectangle has a length 5 inches longer than its width.
\n" ); document.write( "LET WIDTH =W
\n" ); document.write( "LENGTH=W+5
\n" ); document.write( "AREA=L*B=W(W+5)=W^2+5W
\n" ); document.write( "If both the length and the width of the rectangle are increased by 3 inches,
\n" ); document.write( "L NEW =L+3=W+5+3=W+8
\n" ); document.write( "W NEW =W+3
\n" ); document.write( "AREA NEW =(W+8)(W+3)= W^2+8W+3W+24=W^2+11W+24
\n" ); document.write( "the area of the rectangle is increased by 36 square inches.
\n" ); document.write( "W^2+11W+24-W^2-5W=36
\n" ); document.write( "6W=36-24=12
\n" ); document.write( "W=12/6=2
\n" ); document.write( "L=W+5=2+5=7
\n" ); document.write( "Find the original dimensions of the rectangle.
\n" ); document.write( "
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