document.write( "Question 237368: I had a question in my exam today and i couldnt answer it fully
\n" ); document.write( "can you please help\r
\n" ); document.write( "\n" ); document.write( "Qeustion)a)
\n" ); document.write( "find the set of values of 'k' for which the equation 'f(x)=0' has no real solutions.
\n" ); document.write( "answer)
\n" ); document.write( "f(x)=x^2-kx+9, where k is a constant
\n" ); document.write( "b^2-4ac<0
\n" ); document.write( "k^2-4*1*9=k^2-36<0
\n" ); document.write( "k^2<36
\n" ); document.write( "k<6
\n" ); document.write( "-6\n" ); document.write( "(-6,6)
\n" ); document.write( "that was fairly simple, however i struggled on the next part
\n" ); document.write( "Question)b)
\n" ); document.write( "Given that k=4,
\n" ); document.write( "express f(x) in the form (x-p)^2+q, where p and q are constants to be found.
\n" ); document.write( "answer)
\n" ); document.write( "Please help with this question because i really was angry when i couldnt complete it in my exam
\n" ); document.write( "thank you for your cooporation.\r
\n" ); document.write( "\n" ); document.write( "by the way i used '^' to show power of
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #174571 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
b) \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=x%5E2-kx%2B9\" Start with the given function.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=x%5E2-4x%2B9\" Plug in \"k=4\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now let's complete the square.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "To do so, take half of the \"x\" coefficient \"-4\" to get \"-2\". In other words, \"%281%2F2%29%28-4%29=-2\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now square \"-2\" to get \"4\". In other words, \"%28-2%29%5E2=%28-2%29%28-2%29=4\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=x%5E2-4x%2Bhighlight%284-4%29%2B9\" Now add and subtract \"4\". Make sure to place this after the \"x\" term. Notice how \"4-4=0\". So the expression is not changed.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x%5E2-4x%2B4%29-4%2B9\" Group the first three terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x-2%29%5E2-4%2B9\" Factor \"x%5E2-4x%2B4\" to get \"%28x-2%29%5E2\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x-2%29%5E2%2B5\" Combine like terms.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So after completing the square, \"x%5E2-4x%2B9\" transforms to \"%28x-2%29%5E2%2B5\". So \"x%5E2-4x%2B9=%28x-2%29%5E2%2B5\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So \"f%28x%29=x%5E2-4x%2B9\" is equivalent to \"f%28x%29=%28x-2%29%5E2%2B5\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now \"f%28x%29=%28x-2%29%5E2%2B5\" is in the form \"f%28x%29=%28x-p%29%5E2%2Bq\" where p=2 and q=5.
\n" ); document.write( "
\n" );