document.write( "Question 237390: The perimeter of a rectangular garden is 40 ft. The width is 2 ft more than one half the length. Find the length and width. \n" ); document.write( "
Algebra.Com's Answer #174568 by College Student(505)\"\" \"About 
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The Perimeter of a triangle is the sum of its 4 sides. You can express it as: \"P=L%2BL%2BW%2BW\" ...or... \"P=2L%2B2W\"
\n" ); document.write( "The problems tells us the width is 2ft more than half the lenght, therefore:
\n" ); document.write( "\"W=1%2F2L%2B2\"
\n" ); document.write( "Now you can use the perimeter equation, but instead of using L and W, we will use L and the equivalency of W. This will help us figure out the value of L.
\n" ); document.write( "Since P=40 (given)
\n" ); document.write( "\"40=2L%2B2%281%2F2L%2B2%29\"
\n" ); document.write( "When you multiply 2 by 1/2L, the fraction dissapears, but remember to also multiply it by the next digit, which happens to also be 2. Thus...
\n" ); document.write( "\"40=2L%2BL%2B4\"
\n" ); document.write( "\"40-4=3L\"
\n" ); document.write( "\"L=36%2F3\"
\n" ); document.write( "\"L=12\"
\n" ); document.write( "Now figure out W:
\n" ); document.write( "Since \"W=1%2F2L%2B2%29\"
\n" ); document.write( "\"W=%281%2F2%29%2812%29%2B2\"
\n" ); document.write( "\"W=6%2B2\"
\n" ); document.write( "\"W=8\"
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