document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=237230>Question 237230</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of the measure of complementary is ib the ratio of 1:8, find the angle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174526 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174526\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let one angle be x and the other 90-x<BR>\n" );
document.write( "x/(90-x) = 1/8<BR>\n" );
document.write( "8x=90-x<BR>\n" );
document.write( "9x=90<BR>\n" );
document.write( "x=10<BR>\n" );
document.write( "90-10=80<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );