document.write( "Question 237326: what is the equation of the line tangent to the circle x^2+y^2=25 at the point (3,4) ?
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Algebra.Com's Answer #174520 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The general equation of a circle with center at and radius is\r
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\n" ); document.write( "\n" ); document.write( "Hence the circle\r
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\n" ); document.write( "\n" ); document.write( "Must be centered at the origin.\r
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\n" ); document.write( "\n" ); document.write( "The line tangent to the point is perpendicular to the radius segment with endpoints and \r
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\n" ); document.write( "\n" ); document.write( "Determine an equation of the line that contains the aforementioned radius segment by using the two point form of the equation of a line:\r
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\n" ); document.write( "\n" ); document.write( "Where and are the coordinates of the given points.\r
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\n" ); document.write( "\n" ); document.write( "Solve the resulting equation for to put this equation into slope-intercept form. Then determine the slope of the radius segment by inspection of the coefficient on .\r
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\n" ); document.write( "\n" ); document.write( "Next use the fact that the slopes of two perpendicular lines are negative reciprocals, that is:\r
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\n" ); document.write( "\n" ); document.write( "Calculate the negative reciprocal of the slope of the radius segment to get the slope of the tangent.\r
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\n" ); document.write( "\n" ); document.write( "Then use the point-slope form of the equation of a line with the calculated slope and the point to derive the desired equation:\r
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\n" ); document.write( "\n" ); document.write( "Where is the calculated slope and is the point \r
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