document.write( "Question 237320: PLEASE HELP ME SOLVE THIS TRIGONOMETRIC FUNCTIONS:
\n" ); document.write( "Given that sin0=-1/2 and 0 lies in quadrant lV,find the following value.sec 0
\n" ); document.write( "the possible answers are:
\n" ); document.write( "a)-2
\n" ); document.write( "b)square root of 3/2 \"sqrt%283%2F2%29\"
\n" ); document.write( "c)(2/square root of 3)/3 \"%282sqrt%283%29%29%2Fsqrt%283%29\"
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Algebra.Com's Answer #174517 by eggsarecool(46)\"\" \"About 
You can put this solution on YOUR website!
I am going to replace theta with x since i have no way to make the computer display theta.
\n" ); document.write( "So what we have is.
\n" ); document.write( "\"sin%28x%29=-%281%2F2%29\"
\n" ); document.write( "The referance angle that makes sin equal to \"1%2F2\" is 30 degress or \"pi%2F6\"
\n" ); document.write( "If we want this angle in the 4th qudrant we get \"360-30=330\" or \"2pi-pi%2F6=11pi%2F6\"
\n" ); document.write( "So we know that our angle is 330 degrees or \"11pi%2F6\"
\n" ); document.write( "We also know that \"sec%28x%29=1%2Fcos%28x%29\" So we need to find out what cos(x) is to find sec(x).
\n" ); document.write( "So we need to find cos of 330 degrees. The referance angle was 30 degrees and \"cos%2830%29=sqrt%283%29%2F2\". Cos is positive in the 4th quadrent so \"cos%28330%29=sqrt%283%29%2F2\"
\n" ); document.write( "And \"sec%28x%29\" is \"1%2Fcos%28x%29\"
\n" ); document.write( "So \"sec%28330%29=1%2F%28sqrt%283%29%2F2%29=2%2Fsqrt%283%29\"
\n" ); document.write( "And if you rationalize this.
\n" ); document.write( "\"%282%2Fsqrt%283%29%29%2A%28sqrt%283%29%2Fsqrt%283%29%29=%282sqrt%283%29%29%2F3\"
\n" ); document.write( "So choice C is the correct answer.
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