document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=237246>Question 237246</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the general solution for x(n)and y(n)for x(0)=1 and y(0)=0,<BR>\n" );
document.write( "x(n+1)=x(n)+2y(n)<BR>\n" );
document.write( "x(n+1)=3x(n)+2y(n)   n=0,1,2,3,...\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #174487 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=174487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the general solution for x(n)and y(n)for x(0)=1 and y(0)=0,<BR>\n" );
document.write( "x(n+1)=x(n)+2y(n)<BR>\n" );
document.write( "x(n+1)=3x(n)+2y(n)   n=0,1,2,3,...\r<BR>\n" );
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document.write( "If n=0, then substitute this into the equation for n:<BR>\n" );
document.write( "x(0+1)=x(0)+2y(0)\r<BR>\n" );
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document.write( "Since you know the values of x(0) and y(0), substitute these in below:<BR>\n" );
document.write( "x(1)= 1 + 2*0<BR>\n" );
document.write( "x(1)=1\r<BR>\n" );
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document.write( "Now, let n=1, and you have<BR>\n" );
document.write( "x(1+1) = x(1) + 2y(1)<BR>\n" );
document.write( "x(2) = 1 + 2y(1)\r<BR>\n" );
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document.write( "Having said all of this, are you sure you stated this correctly?  I see two different formulas for x(n+1), and I don't see any formula for y(n+1).  Maybe the problem is not stated correctly.  Maybe I just don't know where to go from here.\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje, Retired<BR>\n" );
document.write( "Seminole State College of Florida<BR>\n" );
document.write( "Altamonte Springs Campus </SPAN>\n" );
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