document.write( "Question 237232: the present age of zain is 22 year and his father is 40 years .howmany years ago his father was three times of zain`s age? \n" ); document.write( "

Algebra.Com's Answer #174458 by rapaljer(4671) $\"\"$ $\"About$

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Let x = number of years ago \r
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\n" ); document.write( "\n" ); document.write( "22-x = age of Zain x years ago
\n" ); document.write( "40-x = age of Zain's father x years ago\r
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\n" ); document.write( "\n" ); document.write( "Father's age WAS 3 times Zain's age
\n" ); document.write( "40-x=3(22-x)
\n" ); document.write( "40-x = 66-3x\r
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\n" ); document.write( "\n" ); document.write( "Add +3x to each side:
\n" ); document.write( "40-x + 3x = 66-3x+3x
\n" ); document.write( "40+2x = 66\r
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\n" ); document.write( "\n" ); document.write( "Subtract 40 from each side:
\n" ); document.write( "2x=26\r
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\n" ); document.write( "\n" ); document.write( "Divide by 2:
\n" ); document.write( "x= 13\r
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\n" ); document.write( "\n" ); document.write( "Check: Zain's age was 22-13=9
\n" ); document.write( "Father's age was 40-13= 27, which is 3 times Zain's age.\r
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\n" ); document.write( "\n" ); document.write( "Dr. Robert J. Rapalje \n" ); document.write( "

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